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# r error in match.funfun Buncombe, Illinois

Not strictly necessary but it makes for easier to read & maintain code. There are other forces at play here, but for simplicity just remember to wrap any code up in a function. Here the function definition is not required, we could instead just pass the is.matrix function, as it only takes one argument and has already been wrapped up in a function for The columns values were the metric used for evaluation of each method, and the rows were the results for a given subset.

I was always amused when R seemed to know and would sometimes return my favourite error, reminding me that I was missing the fun: Error in match.fun(FUN) : argument "FUN" is We can see the mean of each column is roughly 0, 2, and 5 as we expected. after the function refers to any other arguments that needs to be passed to the function being applied to the data. First I want to make sure I created that matrix correctly, three columns each with a mean 0, 2 and 5 respectively.

apply(m, 2, mean) #[1] -0.02664418 1.95812458 4.86857792 Great. the function name, without calling it (the calling will happen inside sapply): data[, 29] = sapply(data[,29], nchar) share|improve this answer answered Jun 8 at 13:57 Konrad Rudolph 320k76656906 add a comment| A zero dimensional array is a scalar or a point; a one dimensional array is a vector; and a two dimensional array is a matrix… The margin argument is used to arun kirshna Threaded Open this post in threaded view ♦ ♦ | Report Content as Inappropriate ♦ ♦ Re: an apply question In reply to this post by m p

The actual function is using subsetting to extract all the elements in x that are less than 0, and then counting how many are left are using length. Mike On Tue, Mar 26, 2013 at 6:53 PM, David Winsemius <[hidden email]>wrote: > > On Mar 26, 2013, at 2:51 PM, C W wrote: > > > Dear list, > Copyright © 2016 R-bloggers. In this case we expect to get three numbers at the end, the mean value for each column, so tell apply to work along columns by passing 2 as the second

Can I use my client's GPL software? Thanks in a advance, Mike [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code. Use can probably userollapply for this (via quantmod), but a quick and dirty way is to run sapply or lapply passing a set of index values. Advanced Search Forum Statistical Software R Error in R, help find the problem?

After they are > evaluated sequentially by `sapply` the values 1:10 no longer are named "i" > and so don't naturally fall into the slots you thought you had constructed > Needless to say such circumstances arise quite frequently when working in R, so spending some time getting familiar with apply can be a great boon to our productivity. Interpreting two-way interaction in the presence of quadratic interaction Americanism "to care SOME about something" Is it a Good UX to keep both star and smiley rating system as filters? Not the three numbers we were expecting, try again.

All native R functions use match.fun() for this purpose, and it is recommended for you to do the same if you write code that will be used by other people. sapply(1:3, function(x) x^2) #[1] 1 4 9 lapply is very similar, however it will return a list rather than a vector: lapply(1:3, function(x) x^2) #[[1]] #[1] 1 # #[[2]] #[1] 4 First, apply operators on a matrix or data.frame. Comments are closed.

About a man and a bee more hot questions question feed lang-r about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology You need a reasonably large data set for this to make a noticeable difference, but it's worth keeping in mind regardless. Fine for quickies but not very nice, and will likely turn into a maintainability bomb down the line. Browse other questions tagged r lapply ggmap or ask your own question.

Recent popular posts Election 2016: Tracking Emotions with R and Python The new R Graph Gallery Paper published: mlr - Machine Learning in R Most visited articles of the week How I hope you found these examples helpful. All Rights Reserved. The lapply command is designed for lists.

If you got this far, why not subscribe for updates from the site? It may go away in the future. This also means that if you have an object with the same name as the function you want to use, this whole construct won't work. Here is a simple example: AddSeven<-function(n){n+7} AddSeven(3) [1] 10 M<-matrix(nrow=2,ncol=2,data=c(1,2,3,4),byrow=TRUE) M [,1] [,2] [1,] 1 2 [2,] 3 4 apply(x=M,margin=c(1,2),fun=AddSeven) Error in match.fun(FUN) : argument "FUN" is missing, with no default

Passing a lambda into a function template What's a Shady Word™? If the array we are using is a matrix then we can specify the margin to be either 1 (apply the function to the rows of the matrix) or 2 (apply As an added bonus, match.fun() also allows you to use a character object as the argument, so specifying FUN = 'round' now works as well. To find out more about any of these functions or datasets use the help: ?apply ?lapply ?head ?cars By Garth| 2013-08-28T11:59:40+00:00 December 14th, 2012|R, Teaching|0 Comments Share This Story, Choose Your

What does "Game of the Year" actually mean? Which actual apply function and which specific incantion is required depends on your data, the function you wish to use, and what you want the end result to look like. Related To leave a comment for the author, please follow the link and comment on their blog: Shifting sands. There is a part 2 coming that will look at density plots with ggplot, but firstI thought I would go on a tangent to give some examples of the apply family,

Is it safe for a CR2032 coin cell to be in an oven? Let's have a look: apply(m, 2, function(x) is.matrix(x)) #[1] FALSE FALSE FALSE Not a matrix. I am trying to replace negative values in an array with these values + 24. I have been comparing three methods on a data set.

Join the discussion today by registering your FREE account. How to get the last monday of every month How do I install the latest OpenOffice? Powered by vBulletin™ Version 4.1.3 Copyright © 2016 vBulletin Solutions, Inc. Am I making a parameter > mistake, There is nothing that would naturally "catch" the values.

More or less what we would expect for three normal distributions with the given means and sd of 1. In this case we have passed in m, explicitly naming the y argument in the sapply call. Join Today! + Reply to Thread Results 1 to 2 of 2 Thread: Error in R, help find the problem? David Winsemius Threaded Open this post in threaded view ♦ ♦ | Report Content as Inappropriate ♦ ♦ Re: when to use which apply function?

Does the Many Worlds interpretation of quantum mechanics necessarily imply every world exist? I've encountered this several times, This is time, this is what I am working on, mat <- matrix(c(seq(from=1, to=10), rnorm(10)), ncol=2) a=1; b=5 newfun <- function(x, y, a, b) { x*y+a+b A sample from the data set was generated, and three different methods were applied to that subset. R-bloggers.com offers daily e-mail updates about R news and tutorials on topics such as: Data science, Big Data, R jobs, visualization (ggplot2, Boxplots, maps, animation), programming (RStudio, Sweave, LaTeX, SQL, Eclipse,

You're entirely missing a parameter there. Note that lapply doesn't have a margin argument as it simply applies the function to each of the variables in the data frame. Please check out part 2 where we create a density plot of the values in our matrix. Does the local network need to be hacked first for IoT devices to be accesible?

Dirty Deeds Anyway, a cheap trick is to pass sapply a vector of indexes and write your function making some assumptions about the structure of the underlying data. Join them; it only takes a minute: Sign up Error in match.fun(FUN) : up vote 0 down vote favorite Packages: ggmap, ggplot2 plyr I've used a mapdist function to calculate the I am > trying to replace negative values in an array with these values + 24. > Would appreciate help. Jobs for R usersStatistical Analyst @ Rostock, Mecklenburg-Vorpommern, GermanyData EngineerData Scientist – Post-Graduate Programme @ Nottingham, EnglandDirector, Real World Informatics & Analytics Data Science @ Northbrook, Illinois, U.S.Junior statistician/demographer for UNICEFHealth